The poll, done by American Research Group, shows Newt winning 42% of the tea party vote.
When the voter based is narrowed down to just "definite" voters, Newt gets 32% of the vote, Ron Paul 17, and Mitt Romney 15%.
Saturday, November 26, 2011
Iowa poll: Newt 27, Romney 20, Paul 16
Labels:
American Research Group,
Iowa
Posted by
Josh Gosser
at
Saturday, November 26, 2011
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